Radioactivity
PURPOSE
The purpose of this
activity is to determine the half-life of a radioactive species.
INTRODUCTION
It can be shown
using calculus that whenever the next value of a changing quantity depends on
the current value of the quantity, then the mathematical form of the
relationship is an exponential function.
Examples of exponential relationships include population growth and
radioactive decay. Barring any other
factors such as limited food supply, population growth is an example of an
exponential increase, since the population of the next generation depends on
the number of fertile adults in the current generation. Radioactive decay is an example of
exponential decrease, since the number of radioactive nuclei remaining in the
next instant depends on the number that have not yet
decayed.
Barium -137 is a
radioactive nucleus that naturally decays into Cs - 137 by beta emission. The half-life of this process is on the order
of minutes. The general form of the
equation governing radioactive decay is:
A = A0 e -kt (1)
where A is the activity, A0 is the
activity at time t = 0, k is a constant and t is the time.
The activity is
measured in counts per second (cts/sec). We can determine an average activity by
measuring the total number of counts over a 15 second period and dividing the
counts by 15 (after subtracting out the background activity).
It isn’t possible
to graph equation (1) as written because one of the variables, time, is in the
exponent. However, we can manipulate the
equation to produce the equivalent relation:
ln (A/A0) = -k t (2a)
or
ln (A0 /A) = k t (2b)
where A0 is the average activity over
the first 15 second count. A graph of ln (A0 /A) versus time should be a straight line
with the slope equal to the decay constant, k.
Another useful
concept is half-life ( t ˝ ). The relationship between the decay constant
and half-life is:
k t˝ = ln(2)
= 0.693 (3)
For a decay process
following equation (1), the activity of a radioactive sample will be exactly
one half the activity at some initial time after one
half-life of time has passed.
INSTRUCTIONS
Obtain the
background radiation count by collecting data for two minutes away from the
radioactive source. Since counts will be
collected for 15 seconds at a time, divide this number by 8 to determine the
average background activity over a fifteen second time interval and record it
on the data sheet.
Extract a radioactive
barium sample by forcing eluting solution through the sample holder and
collecting the solution in a plastic cup.
Place the Geiger counter directly over the solution to obtain the most
accurate data. Record the total counts
for 15 seconds then wait 15 seconds before starting another count. Be sure to clear the counter before recording
the total counts for the next fifteen seconds.
Repeat this process of ‘15 seconds on, 15 seconds off’ for at least ten
minutes.
Subtract the
background count (for 15 seconds) from each raw count. Divide that number by 15 to obtain the number
of counts per second and record the activity in the next column of the data
table. The first activity recorded will
serve as the value of A0 (which is the activity, A, at time t =
0). Complete the rest of the table by
dividing this value of A0 by each value of A. Next, find the natural log of each ratio.
Construct a graph and graph ln (A0 /A) versus t, where t is the initial
time of the 15 second count (0, 30, 60 secs.,
etc.). Find the slope to determine the
decay constant. Also calculate the
half-life of barium 137.
Use the adjusted
15-second count to check if the conditions of the half-life are being met. To do this, choose a time in the data table
and note the activity. Add the
calculated half-life to this time and estimate the activity of the sample at
that time. If half-life is a valid
concept, then the second activity should be approximately one-half of the
first.
RADIOACTIVITY – REPORT SHEET
Background reading
for 2 minutes ________________
Average background for 15 seconds ________________
Elapsed time |
Counts / 15 secs |
Adjusted count |
Counts / second |
A0 / A |
ln(A0/A) |
0 seconds |
|
|
A0 = |
|
|
30 |
|
|
|
|
|
60 |
|
|
|
|
|
90 |
|
|
|
|
|
120 |
|
|
|
|
|
150 |
|
|
|
|
|
180 |
|
|
|
|
|
210 |
|
|
|
|
|
240 |
|
|
|
|
|
270 |
|
|
|
|
|
300 |
|
|
|
|
|
330 |
|
|
|
|
|
360 |
|
|
|
|
|
390 |
|
|
|
|
|
420 |
|
|
|
|
|
450 |
|
|
|
|
|
480 |
|
|
|
|
|